WebApr 22, 2024 · Prime factors of 657: 3 × 3 × 73. Prime factors of 963: 3 × 3 × 107. HCF of 657 and 963: = 3 × 3 = 9. According to question: the HCF of 657 and 963 is expressible in the form 657x + 963 × -15 Web315 = 3 × 3 × 5 × 7. Find the prime factorization of 693. 693 = 3 × 3 × 7 × 11. To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 3 × 3 × …
If the HCF of 657 and 963 is expressible in the form 657 x + 963 …
WebOct 10, 2024 · 615 and 963. To find: We have to find the value of the largest number which divides 615 and 963 leaving the remainder 6 in each case. Solution: If the required number divide 615 and 963 leaving remainder 6 in each case, then this means that number will divide 609(615 - 6) and 957(963 - 6) completely. Now, we just have to find the HCF of … WebMay 13, 2024 · To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF. Consider HCF be x. In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases. 609 = 3 x 3 x 29 957= 3 x 11 x 29 ⇒ x = 3 x 29 = 87_____answer ∴ largest number which divides 615 and 963 leaving ... fiend in tagalog
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WebAug 5, 2024 · Math Secondary School answered What is HCF of 615 and 963 ? Advertisement Answer 3 people found it helpful saumya983 3 is the H.C.F. of 615 and … WebMay 25, 2024 · 615 = 3*3*29 963 = 3*11*29 HCF = 3*29 = 87 87 is the largest number which divides 615 and 963 leaving remainder 6 in each case. Advertisement llTheUnkownStarll Firstly, the required numbers which on dividing doesn’t leave any remainder are to be found. This is done by subtracting 6 from both the given numbers. WebFeb 21, 2024 · Find the largest number which divides 615 and 963 leaving remainder 6 in each case. ... So, the numbers are 615 – 6 = 609 and 963 – 6 = 957. Now, if the HCF of 609 and 957 is found, that will be the required number. By applying Euclid’s division lemma . 957 = 609 x 1+ 348 . 609 = 348 x 1 + 261 . 348 = 216 x 1 + 87 . fiendish 2 font