If x2 + 2ax + 10 – 3a 0 for all x then
WebThe given equation is, 2 2 = 0 Here two cases are possible : x – a > 0 then x – a = x – a ∴ Eq. Becomes 2 2 = 0 Or x 2 2 = 0 ⇒ x = 2a ± √4a 2 ⇒ x = a ± a√2 ∴ Eq. becomes 2 + 2a (x – a) – 3a 2 = 0 Or x 2 2 = 0 + 20a /2 ⇒ x = -2a ± 2a√6/2 x = -a ± a√6 Thus the solution set is { a ± a√2, -a ± a√6} Other Related Questions on Algebra
If x2 + 2ax + 10 – 3a 0 for all x then
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WebIf the roots of the equation x 2−2ax+a 2+a−3=0 are real and less than 3, then Hard View solution > lf both roots of the equation x 2−2ax+a 2−1=0 lie in the interval (−3,4), then sum of the possible integral values of a is Medium View solution > View more Web摘要 z题目编号21 若f(x)在(ab)内存在,xe(ab),则f( 南阳市十九中历年来分班考试卷,数学 南阳市第十九中分班考试数学卷子
WebCorrect options are B) and C) The given inequality (x−3a)(x−a−3)<0 satisfies for all x in interval 1≤x≤3 Hence, x=1,2,3 should also satisfy the given inequality. We find solutions for x= 1,2,3 x=1 ⇒ (1−3a)(−a−2)<0 ⇒ (1−3a)(a+2)>0 ⇒ Solution for above inequality are a>−2 and a<1/3 .......A x=2 ⇒ (2−3a)(−a−1)<0⇒ (2−3a)(a+1)>0 WebIf x^2+2ax+10-3a>0 for all x then . Answers (1) Solution: We have , if , Here . Posted by Deependra Verma. View full answer Post Answer. Similar Questions. Is "OXO Process" same as "KOCH Reaction" used for preparing of Carboxylic Acid? i have selected ctse for medical but i got it for engineering can i change it ...
Web4 apr. 2024 · The linear factors are being deduced from the polynomials in order to factorise the polynomials. As per the question, for all x , x 2 + 2 a x + 10 − 3 a > 0 . We know that, … <5 Easy Solution Verified by Toppr Correct option is B) Given equation- x …
Web11 apr. 2024 · Equation x 2 + 2ax + 10 - 3a > 0 for all x ∈ R ⇒ (2a) 2 - [4 × (10 - 3a)] < 0 ⇒ 4a 2 - [40 - 12a] < 0 ⇒ 4a 2 + 12a - 40 < 0 ⇒ a 2 + 3a - 10 < 0 ⇒ (a + 5) (a - 2) < 0 ∴ -5 < …
Web23 feb. 2024 · If x2 + 2ax + 10 - 3a > 0 for all x ∈ R, then. ← Prev Question Next Question →. 0 votes . 67 views. asked Feb 23, 2024 in Quadratic Equations by Ritikgupta (38.4k … fresh stop diner full menu<5 Medium Solution Verified by Toppr Correct option is B) For given condition discriminant of the given quadratic should be negative, ⇒(2a) 2−4(10−3a)<0⇒a 2+3a−10<0 ⇒(a−2)(a+5)<0⇒−5 freshstop head office cape townWeb下载量 0. 百度教育 百度题库 试卷 中考 高一 2016 2024 物理 江西 相关推荐. 2016-2024学年高一物理期中考试试题及参考答案; 赣州市厚德外国语学校20162024学年高一上学期期中考试数学试题含答案 ... fresh stone crabs near meWeb(A) x2 + y2 – 4ax = 0 (B) x2 + y2 – 2ax = 0 (C) x2 + y2 + 2ax = 0 (D) x2 + y2 + 4ax = 0 4. If the normal to a parabola y2 = 4ax at P meets the curve again in Q and if PQ and the normal. at Q makes angles and respectively with the x-axis then tan … father castelliWebCorrect option is A) Given equation x 2−2ax+a 2+a−3=0…(1) ⇒(x−a) 2=3−a Since, (x−a) 2≥0 ⇒3−a≥0 ⇒a≤3 We have a formula for solving quadratic equation ax 2+bx+c=0 is x= 2a−b± b 2−4ac Now, the roots of equation (1) are x= 2.1−(−2a)± (−2a) 2−4.1.(a 2+a−3) x=a± 3−a Since, roots are less than 3. a+ 3−a<3 ⇒ 3−a<3−a ⇒3−a<9+a 2−6a ⇒a … fresh stop specials 2021Web31 mei 2024 · For all x^2 , x^2 + 2ax +(10-3a) >0 , then the interval in which 'a' lies is ?fasttt 2 See answers Advertisement Advertisement aliya346 aliya346 D<0⇒4 a 2. … freshstop specials caledonWebFor all x,x 2+2ax+10−3a>0, then the interval in which a lies is Medium View solution > Find all values of a for which the inequality (a−1)x 2−(a+1)x+a+1>0 is satisfied for all real x. Medium View solution > View more Get the Free Answr app Click a picture with our app and get instant verified solutions father cat grooming kittens